Winter Peak Design
Consider the CAV system analyzed under peak cooling load condition in Example 19.1. The same space is to be maintained at 72°F (25.5°C) and 50% RH. The total heating load of the space is 150,000 Btu/h (44 kW) with an SHR of 0.8. The outdoor design condition is 40°F (4.4°C) dry bulb and 40% RH. The same amount of ventilation air (1000 ft³/min or 472 L/s) is needed. Design the necessary heating and humidification equipment assuming saturated steam at 200°F (93°C) is available and the supply airflow rate is kept at the summer design peak value of 17,140 lba/h (2.2 kg/s).
The supply air dry-bulb temperature should not exceed 105°F (40.5°C).
Figure: See Figure 19.5a and b.
Assumptions: The location is at sea level. The duct heat transfer and the fan air temperature rise are ignored for simplicity.
Given: m˙a=17,140 lba/h,SHRspace=0.80,Q˙space,tot=150,000 Btu/hs
Outdoorairconditions: Tdb,o=40°F,ϕo=0.40,V˙0=1000 ft3/min
Spaceconditions: T7=72°F and ϕ7=0.5,Tdb,6<105°F
Find: m˙steam,Q˙ph , and Q˙hc
Lookup values: Specific volume v0=12.65 ft3/lba, humidity ratio W0=0.0021 lbw/lba,W7=0.0084 lbw/lba,h7=26.4 Btu/lba, specific heat of air ca=0.24 Btu/lba⋅°F, and enthalpy of steam hsteam=1146 Btu/lbw.
We will illustrate the use of the graphical procedure as previously.
1. Locate specified points 0 and 7 on the psychrometric chart (see Figure 19.5b),
which are specified from the problem statement.
2. Determine outdoor air mass flow rate.
The outdoor air mass flow is given by
=12.65 ft3/lba1000 ft3/min × 60 min/h=4743 lba/h
Note that this mass flow rate is over 13% higher than the previous case and is attributed to the difference in the specific volumes of outdoor air between summer and winter conditions.
3. Locate mixed air condition point 1.
The inverse relation between mass flows and line segment lengths (Equation 13.32) is used to locate 1. The ratio of air mass flows is (4,743/17,140) = 0.277. The dry-bulb temperature and humidity ratios can be calculated from the chart or just as simply using the weighted average rule:
m˙a2m˙a1=h3 – h1h2 – h3=W3 – W1W2 – W3 (13.32)
a. The mixed-air temperature: Tdb,1=[0.277×40°F+(1−0.277)×72°F]=63.15°F
b. The humidity ratio: W1=[0.277×0.0021 lbw/lba+(1 − 0.277)×0.0084 lbw/lba]=0.00665 lbw/lba.
The corresponding moist-air enthalpy is read from the psychrometric chart, h1=22.4 Btu/lba.
4. Determine supply air condition point 5.
As previously discussed, the slope of line 5–7 is equal to the inner scale of the protractor corresponding to SHRspace=0.80. We determine enthalpy h5 of the specified supply air mass flow rate as follows:
=35.15 Btu/lba
The intersection of the enthalpy line corresponding to 35.15 Btu/lba and the line 6–7 yields a point whose corresponding drybulb value is Tdb,5=102°F (this is acceptable since it is lower than the stipulated maximum value of 105°F). The corresponding humidity ratio W5=0.0096 lbw/lba.
5. Determine the amount of steam needed.
This is easily calculated since the entering and leaving humidity ratio of the airstreams are known:
=17,140 lba/h×(0.0096 – 0.00665) lbw/lba
=50.56 lbw/h
6. Compute sensible heating needed.
We can use different combinations of preheat and reheat amounts to attain the desired effect. One option is to assume that all heating is provided by the preheater. This is then a simple heating and humidication problem as treated in Section 13.6.6. We draw a line from point 6 parallel to the outer scale of the protractor corresponding to 1146 (since enthalpy of steam hsteam=1146 Btu/lbw) that intersects the horizontal line from point 1 at point 2. This is determined to be Tdb,2=100.8°F and h2=31.6 Btu/lba.
Finally, the sensible heat provided by the heating coil is found:
= 157,688 Btu/h