Question 9.5: Writing Equations for the Formation of an Insoluble Ionic Co......

Writing Equations for the Formation of an Insoluble Ionic Compound

When solutions of NaCl and AgNO_3 are mixed, a white solid forms. Write the ionic and net ionic equations for the reaction.

Step-by-Step
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STEP 1 Write the ions of the reactants.

STEP 2 Write the combinations of ions, and determine if any are insoluble.

When we look at the ions of each solution, we see that the combination of Ag ^{+} and Cl^- forms an insoluble ionic compound.

STEP 3 Write the ionic equation including any solid. In the ionic equation, we show all the ions of the reactants. The products include the solid AgCl that forms along with the remaining ions Na ^{+}\text{ and }NO _3^{-}.

Ag ^{+}(a q)+ NO _3^{-}(a q)+ Na ^{+}(a q)+ Cl ^{-}(a q) \longrightarrow AgCl (s)+ Na ^{+}(a q)+ NO _3^{-}(a q)

STEP 4 Write the net ionic equation. We remove the Na ^{+}\text{ and }NO _3{ }^{-} ions, known as spectator ions, which are unchanged. This gives the net ionic equation, which only shows the ions that form a solid precipitate.

\begin{gathered} Ag ^{+}(a q)+\underbrace{ \cancel{NO_3{ }^{-}(a q)}+ \cancel{Na ^{+}(a q)}}_{\text {Spectator ions }}+ Cl ^{-}(a q) \longrightarrow AgCl (s)+\underbrace{ \cancel{Na ^{+}(a q)}+ \cancel{NO _3(a q)}}_{\text {Spectator ions }} \\\\ Ag ^{+}(a q)+ Cl ^{-}(a q) \longrightarrow AgCl (s) \text { Net ionic equation } \end{gathered}
Mixture (new combinations) Product Soluble
Ag ^{+}(a q)+ Cl ^{-}(a q) AgCl No
Na ^{+}(a q)+ NO _3^{-}(a q) NaNO_{3} Yes

 

Type of

Equation

Chemical AgNO _3(a q) \quad+ NaCl (a q) \longrightarrow AgCl (s)+ NaNO _3(a q)
lonic Ag ^{+}(a q)+ NO _3^{-}(a q)+ Na ^{+}(a q)+ Cl ^{-}(a q) \rightarrow AgCl (s)+ Na ^{+}(a q)+ NO _3^{-}(a q)
Net lonic Ag ^{+}(a q) \quad+ Cl ^{-}(a q) \longrightarrow AgCl (s)
9.5 ans 1

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