Question 4.SP.11: A 100-lb force acts as shown on a 300-lb crate placed on an ...

A 100-lb force acts as shown on a 300-lb crate placed on an inclined plane. The coefficients of friction between the crate and the plane are \mu_s = 0.25 and \mu_k = 0.20. Determine whether the crate is in equilibrium, and find the value of the friction force.

STRATEGY: This is a friction problem of the first type: You know the forces and the friction coefficients and want to determine if the crate moves. You also want to find the friction force.

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MODELING and ANALYSIS:

Force Required for Equilibrium. First determine the value of the friction force required to maintain equilibrium. Assuming that F is directed down and to the left, draw the free-body diagram of the crate (Fig. 1) and solve the equilibrium equations:

\begin{aligned}&+\nearrow \Sigma F_x=0: \quad 100  lb-\frac{3}{5}(300  lb)-F=0 \\&F=-80  lb \quad \pmb{F}=80  lb \nearrow \\&+\nwarrow \Sigma F_y=0: \quad N-\frac{4}{5}(300  lb)=0 \\&N=+240  lb \quad \pmb{N}=240  lb \nwarrow \end{aligned}

The force F required to maintain equilibrium is an 80-lb force directed up and to the right; the tendency of the crate is thus to move down the plane.

Maximum Friction Force. The magnitude of the maximum friction force that may be developed between the crate and the plane is

F_m=\mu_s N \quad \quad F_m=0.25(240  lb)=60  lb

Because the value of the force required to maintain equilibrium (80 lb) is larger than the naximum value that may be obtained (60 lb), equilibrium is not maintained and the crate will side down the plane.

Actual Value of Friction Force. The magnitude of the actual friction force is

F_{\text {actual }}=F_k=\mu_k N=0.20(240  lb)=48  lb

The sense of this force is opposite to the sense of motion; the force is thus directed up and to the ight (Fig. 2):

\pmb{F}_{\text {actual }}=48  lb \nearrow

Note that the forces acting on the crate are not balanced. Their resultant is

\frac{3}{5}(300  lb)-100  lb-48  lb=32  lb \swarrow

REFLECT and THINK: This is a typical friction problem of the first type. Note that you used the coefficient of static friction to determine if the crate moves, but once you found that it does move, you needed the coefficient of kinetic friction to determine the friction force.

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