Question 7.12: A dc machine induces an EMF of 240 V at 1500 rpm. Find the d...
A dc machine induces an EMF of 240 V at 1500 rpm. Find the developed torque for an armature current of 25 A.
Power developed, P = E × I_{a}
= 240 × 25
= 6000 W
Again, P = T × ω where ω is the angular velocity in radians per second.
\omega=\frac{2 \pi N}{60} where N is in rpm
Therefore, T=\frac{P}{2 \pi N / 60}=\frac{60}{2 \pi} \frac{P}{N}=9.55 \times \frac{6000}{1500}=38.2 Nm
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