A gas occupies 3.00 L at 2.00 atm pressure. Calculate its volume when we increase the pressure to 10.15 atm at the same temperature. Strategy First, we identify the known quantities. Because [latex]T_1 and T_2[/latex] are the same in this example and consequently cancel each other, we don’t need to know the temperature. We use the relationship [latex]P_1V_1 = P_2V_2[/latex] and solve the combined gas law for [latex]V_2[/latex].

Solution Initial: [latex]P_1[/latex] = 2.00 atm [latex]V_1[/latex] = 3.00 L Final: [latex]P_2[/latex] = 10.15 atm [latex]V_2[/latex] = ? [latex]V_2 = \frac{P_1V_1 \cancel{T_2}}{\cancel{T_1} P_2}=\frac{(2.00 \cancel{atm}) (3.00 L)}{10.15 \cancel{atm}}= 0.591 L [/latex]

Question 5.1: A gas occupies 3.00 L at 2.00 atm pressure. Calculate its vo...

Introduction to General, Organic and Biochemistry

A gas occupies 3.00 L at 2.00 atm pressure. Calculate its volume when we increase the pressure to 10.15 atm at the same temperature.

Strategy
First, we identify the known quantities. Because $T_1 and T_2$ are the same in this example and consequently cancel each other, we don’t need to know the temperature. We use the relationship $P_1V_1 = P_2V_2$ and solve the combined gas law for $V_2$ .

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