Question 2.11: A heat exchanger has an overall heat transfer coefficient of...

A heat exchanger has an overall heat transfer coefficient of 120 W/m2K. Superheated steam enters the tubes at 250 °C and exits the exchanger at 400 °C. Hot gases on the shell side enter at 900 °C and exchange heat with the steam. The capacity rate of steam is 200 000 W/K and that of the gases is 300 000 W/K. What is the effectiveness? Using the formula for NTU for a counter-current shell and tube, determine the required surface area of the heat exchanger. What is the temperature of the gases leaving the exchanger?

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NTU = \frac{\ln \left(\frac{1  –  \epsilon  C_{min}/C_{max}}{1 – \epsilon } \right) }{1  –  C_{min}/C_{max} }

The actual heat transfer is q = C_{steam} \times (400  –  250) = 30  MW.

q_{min} =  C_{min}(900  –  250) = 130  MW. The effectiveness, \epsilon = q/q_{min} = 30/130 = 0.23.
We know that NTU = UA/C_{min} = 120 \times A/200  000. From the formula for a single counter-flow tube and shell exchanger:

NTU = \frac{\ln \left(\frac{1  –  0.23  \times  20  000/30  000}{1  –  0.23 } \right) }{1  –  20  000/30  000 }

Therefore, A = 0.285 × 200 000/120 = 475 m². The gases exit temperature is determined by: q = C_{gases}(900  –  T_{exit}), 30 \times 106 = 300  000 \times (900  –  T_{exit}), and T_{exit} = 800  °C.

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