A liquid-phase double-replacement reaction between bromine cyanide (A) and methylamine takes place in a PFR at 10°C and 101 kPa . The reaction is first-order with respect to each reactant, with [latex] k_A = 2.22 L mol^{-1} s^{-1} [/latex] . If the residence or space time is 4 s, and the inlet concentration of each reactant is [latex] 0.10 mol L^{-1} [/latex] , determine the concentration of bromine cyanide at the outlet of the reactor .

The reaction is : [latex] BrCN(A) + CH_3NH_2(B) \rightarrow NH_2CN(C) + CH_3Br(D) [/latex] Since this is a liquid-phase reaction, we assume density is constant. Also, since the inlet concentrations of A and B are equal, and their stoichiometric coefficients are also equa l , at all points, [latex] c_A = c_B [/latex] . Therefore, the rate law may be written as : [latex] ( -r_A) = k_Ac_A^2 [/latex] (A) From equations 15.2-16 and (A), [latex] \frac {dc_A}{dt} + ( -r_A) = 0 [/latex] (15.2-16) [latex] -dc_A / dt = k_Ac_A^2 [/latex] which integrates to [latex] k_At = \frac {1}{c_A} - \frac{1}{c_{Ao}} [/latex] On insertion of the numerical values given for [latex]k_A [/latex], t, and [latex]c_{Ao} [/latex], we obtain [latex] c_A = 0.053 mol L^{-1} [/latex]

Question 15.2: A liquid-phase double-replacement reaction between bromine c...

Introduction to Chemical Reaction Engineering and Kinetics

A liquid-phase double-replacement reaction between bromine cyanide (A) and methylamine takes place in a PFR at 10°C and 101 kPa . The reaction is first-order with respect to each reactant, with $k_A = 2.22 L mol^{-1} s^{-1}$ . If the residence or space time is 4 s, and the inlet concentration of each reactant is $0.10 mol L^{-1}$ , determine the concentration of bromine cyanide at the outlet of the reactor .

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