Question 8.6: A long cylindrical shell is constructed of carbon steel with...
A long cylindrical shell is constructed of carbon steel with a yield stress of 38,000 psi and a radius of 36 in. If the stiffeners are spaced at a 4 ft interval, calculate the required shell thickness and the size of stiffening rings for an external pressure of 10 psi at 100 °F.
Let
t = 0.1875 in., \frac{L}{D_{ o }} = 0.67, \frac{D_{ o }}{t} = 384.
From Figure 8.10,
A = 0.00028.
From Figure 8.11,
B = 4000 psi.
Hence,
P=\frac{4}{3}\left(\frac{4000}{384}\right)=10.4 \text { psi. }Use a shell thickness of 3/16 in., and try a 3 \times 3 \times \frac{3}{16} angle stiffening ring:
A_{ s }=1.09 in ^{2} and I=0.9622 \text { in. }{ }^{4} ,
B=\frac{3}{4} \frac{(10)(72)}{0.1875+1.09 / 48}=2570 \text { psi }From Figure 8.11, A=0.00018, so
I=\frac{72^{2} \times 48(0.1875+1.09 / 48)(0.00018)}{14}= 0.67 \text { in. } ^{4} acceptable
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