Question 7.14: A magnetic circuit has a mean core length of 160 cm and unif...
A magnetic circuit has a mean core length of 160 cm and uniform cross-section of 5 cm² . It has an air-gap of 0.8 mm and is wound with a coil of 1200 turns. Determine the self-inductance of the coil if the core material has a relative permeability of 1600.
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The core reluctance is
R_{c} = l_{c} / μ_{0} μ_{r} A = (160 × 10^{-2} )/(4π × 10^{-7} × 1600 × 5 × 10^{-4} )
= 1.59 × 10^{6}
The air-gap reluctance is
R_{g} = l_{g} / μ_{0} A = (0.8 × 10^{-3} )/(4π × 10^{-7} × 5 × 10^{-4} )
= 1.27 × 10^{6}
R(total) = (1.59 + 1.27) 10^{6} = 2.86 × 10^{6}
Coil inductance L = N² / R = (1200)² /(2.86 × 10^{6} ) = 0.5 H
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