Question 7.14: A magnetic circuit has a mean core length of 160 cm and unif...

A magnetic circuit has a mean core length of 160 cm and uniform cross-section of 5 cm² . It has an air-gap of 0.8 mm and is wound with a coil of 1200 turns. Determine the self-inductance of the coil if the core material has a relative permeability of 1600.

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

The core reluctance is

R_{c} = l_{c} / μ_{0} μ_{r} A = (160 × 10^{-2} )/(4π × 10^{-7} × 1600 × 5 × 10^{-4} )

= 1.59 × 10^{6}

The air-gap reluctance is

R_{g} = l_{g} / μ_{0} A = (0.8 × 10^{-3} )/(4π × 10^{-7} × 5 × 10^{-4} )

= 1.27 × 10^{6}

R(total) = (1.59 + 1.27) 10^{6} = 2.86 × 10^{6}

Coil inductance                 L = N² / R = (1200)² /(2.86 × 10^{6} ) = 0.5 H

Related Answered Questions

Question: 7.12

Verified Answer:

Writing the mesh equation for the two meshes, we h...