Question 9.9: A potassium iodide solution may be used in a diet that is lo...
A potassium iodide solution may be used in a diet that is low in iodine. A KI solution is prepared by dissolving 5.0 g of KI in enough water to give a final volume of 250 mL. What is the mass/volume percent (m/v) of KI in the solution?
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STEP 1 State the given and needed quantities.
ANALYZE THE PROBLEM | Given | Need | Connect |
5.0 g of KI solute, 250 mL of KI solution | mass/volume percent (m/v) | \frac{mass of solute }{volume of solution} \times 100% |
STEP 2 Write the concentration expression.
Mass/volume percent (m/v) = \frac{mass of solute }{volume of solution} \times 100 %
STEP 3 Substitute solute and solution quantities into the expression and calculate.
Mass/volume percent (m/v) = \overset{Two SFs}{\underset{Two SFs}{\frac{5.0 g KI}{250 mL solution}}} \times 100 % = 2.0% \underset{Two SFs}{(m/v) KI solution }
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