Question 12.8: A rectangular channel, 9.14 m wide, carries 7.64 m^3/s when ...
A rectangular channel, 9.14 m wide, carries 7.64 \mathrm{~m}^{3} / \mathrm{s} when flowing 914 mm deep. (i) What is the specific energy? (ii) Is the flow tranquil or rapid?
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(i) We know from Eq. (12.31) that
E_{s}=h+\left(\frac{q^{2}}{2 g}\right) \frac{1}{h^{2}}Or E_{s}=0.914+\frac{1}{2 \times 9.81 \times(0.914)^{2}}\left(\frac{7.64}{9.14}\right)^{2}
= 0.957 m
(ii) From Eq. (12.32),
h_{c}=\left(q^{2} / g\right)^{1 / 3} h_{c}=\left[\left(\frac{7.64}{9.14}\right)^{2} \frac{1}{9.81}\right]^{1 / 3}=0.415 \mathrm{~m}=415 \mathrm{~mm}Therefore, the flow is tranquil since the depth of flow is grater than the critical depth.
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