Question 7.10: A salt shaker contains 73.7 g of NaCl. How many moles of NaC...
A salt shaker contains 73.7 g of NaCl. How many moles of NaCl are present?
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STEP 1 State the given and needed quantities.
ANALYZE THE PROBLEM | Given | Need | Connect |
73.7 g of NaCl | moles of NaCl | molar mass |
STEP 2 Write a plan to convert grams to moles.
grams of NaCl \boxed{Molar mass } → moles of NaClSTEP 3 Use Avogadro’s number to write conversion factors.
(1 \times 22.99) + (1 \times 35.45) = 58.44 g/mole
\boxed{\begin{array}{l} 1 mole of NaCl = 58.44 g of NaCl \\ \frac{58.44 g NaCl}{1 mole NaCl} and \frac{1 mole NaCl}{58.44 g NaCl} \end{array}}STEP 4 Set up the problem to calculate the number of particles.
73.7 \cancel{g NaCl} \times \boxed{\frac{1 mole NaCl}{58.44 \cancel{g NaCl}} } = 1.26 moles of NaClRelated Answered Questions
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