Question 6.PR.1: A sample of 40 observations has a standard deviation of 20. ...
A sample of 40 observations has a standard deviation of 20. Estimate the 95% confidence interval for the standard deviation of the population.
The 95% c.i. for the variance is \frac{39\times30^{2}}{59.34}\leqslant\sigma^{2}\leqslant\frac{39\times30^{2}}{24.43} where 24.43 and 59.34 are the limits cutting off 2.5% in each tail of the \chi^{2} distribution, so the c.i. for σ is [16.21, 25.29].
Related Answered Questions
Question: 6.1
Verified Answer:
Since we are using the 95% confidence level the cr...
Question: 6.PR.3
Verified Answer:
\chi^{2}=3.28<3.84, the 95% crit...
Question: 6.PR.9
Verified Answer:
(a) The correct observed and expected values are
...
Question: 6.PR.7
Verified Answer:
\chi^2(4) = 8.12 which is not signi...
Question: 6.PR.5
Verified Answer:
Using the data as presented, with expected values ...
Question: 6.EX.6
Verified Answer:
The answer is summarised in this Excel table:
...
Question: 6.EX.5
Verified Answer:
The two variances are s^{2}_{A}=0.031[/late...
Question: 6.EX.4
Verified Answer:
The expected values are:
Higher education
A l...
Question: 6.EX.3
Verified Answer:
The test statistics are for (16, 55, 29) \c...
Question: 6.EX.2
Verified Answer:
The calculation of the test statistic is
Outco...