Question 16.2: A set of six M8 bolts are used to provide a clamping force o...
A set of six M8 bolts are used to provide a clamping force of 20 kN between two components in a machine. If the joint is subjected to an additional load of 18 kN after the initial preload of 8.5 kN per bolt has been applied, determine the stress in the bolts. The stiffness of the clamped components can be assumed to be three times that of the bolt material. The proof stress of the low carbon steel bolt material is 310 MPa.
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Taking k_c = 3k_b,
F_{b}=F_{i}+\frac{k_{b}}{k_{b}+k_{c}} F_{e}=F_{i}+\frac{k_{b}}{k_{b}+3 k_{b}} F_{e}=F_{i}+\frac{1}{4} F_{e}=8500+\frac{18,000 / 6}{4}=9250 NF_{c}=F_{i}-\frac{k_{c}}{k_{b}+k_{c}} F_{e}=F_{i}-\frac{3 k_{b}}{k_{b}+3 k_{b}} F_{e}=F_{i}-\frac{3}{4} F_{e}=8500-\frac{3(18,000 / 6)}{4}=6250 N
As F_c is greater than zero, the joint remains tight. The tensile stress area for the M8 bolt can be determined from
d_{p}=8-0.649519 \times 1.25=7.188 mmd_{r}=8-1.226869 \times 1.25=6.466 mm
A_{t}=\frac{\pi}{16}(7.188+6.466)^{2}=36.61 mm ^{2}
The stress in each bolt is given by
\sigma=\frac{F_{b}}{A_{t}}=\frac{9250}{36.61 \times 10^{-6}}=252.7 MPaThis is 82% of the proof stress. The bolts are therefore safe.
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