Question 19.17: A short pendulum oscillates with s.h.m. such that its accele...

A short pendulum oscillates with s.h.m. such that its acceleration a (in m s^{−2}) is related to its displacement x (in m) by the equation a = −300x. Determine the frequency of the oscillations.

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

Angular frequency ω = 2πf so, in acceleration
equation, a = ω²x = –4π²x
meaning 4π²f² = 300 s^{−2} , therefore

f = \sqrt{\frac{300}{4 \pi^{2}}} = 2.76  Hz \approx 2.8  Hz

Related Answered Questions