Question 7.4: A sign outside a pub is attached to a light rod of length 1 ...

A sign outside a pub is attached to a light rod of length 1 m which is freely hinged to the wall and supported in a vertical plane by a light string as in the diagram. The sign is assumed to be a uniform rectangle of mass 10 kg. The angle of the string to the horizontal is 25°.

i) Find the tension in the string.
ii) Find the magnitude and direction of the reaction force of the hinge on the sign.

fig 7.28
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i) The diagram shows the forces acting on the rod, where R_{H} and R_{V} are the magnitudes of the horizontal and vertical components of the reaction R on the rod at the wall.

Taking moments about O

R × 0 – 10g × 0.5 + T sin 25° × 1 = 0

⇒     T sin 25° = 5g

T = 116

The tension is 116 N.

ii) You can resolve to find the reaction at the wall.

Horizontally:                 R_{H} = T cos 25°

⇒          R_{H} = 105

Vertically:      R_{V} + T sin 25° = 10g

⇒              R_{V} = 10g – 5g = 49

R = \sqrt{105² + 49²}

= 116

θ = arctan (\frac{49}{105}) = 25°

The reaction at the hinge has magnitude 116 N and acts at 25 above the horizontal.

fig 7.29
fig 7.30

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