Question 20.13: A signal has an input power 5.0 mW and an output power of 0....
A signal has an input power 5.0 mW and an output power of 0.000 2 mW. What is the attenuation in dB?
Attenuation = 10 lg \left( \frac{P_{1}}{P_{2}}\right) = 10 lg \left(\frac{5.0}{0.0002}\right)
= 44 dB (or a gain of –44 dB).
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