Question 17.2: A single row of openings is alternately spaced on 4 and 3.5 ...
A single row of openings is alternately spaced on 4 and 3.5 in. center-to-center spacings. The opening diameters also alternate, with a 1.5 in. diameter opening followed by a 1.25 in. diameter opening. What is the minimum ligament efficiency for setting the thickness?
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Calculate the equivalent diameter D_{E} to be used in the ligament-efficiency equation as
D_{ E } =0.5(1.5+1.25)=1.375 in
The ligament efficiency is based on the minimum spacing of p=3.5 in. using the equivalent diameter D_{E} =1.375 in.:
e_{ m }=e_{ b }=\frac{3.5-1.375}{3.5}=0.607Related Answered Questions
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