Question 26.3.40: A thin cylinder of radius r and thickness t when subjected t...

A thin cylinder of radius r and thickness t when subjected to an internal hydrostatic pressure p causes a radial displacement u, then the tangential strain caused is

(a) \frac{du}{dr}             (b) \frac{1}{r} \cdot \frac{du}{dr}             (c) \frac{u}{r}             (d) \frac{2u}{r} .

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(c)

EXPLANATION

Radial displacement = u
Initial radius = r
Final radius = r + u

Tangential strain = Circumferential strain = \frac{\text { Final circumference }-\text { Initial }}{\text { Initial circumference }} \\ \space \\ =\frac{2 \pi(r+u)-2 \pi r}{2 \pi r}=\frac{2 \pi u}{2 \pi r}=\pmb{\frac{ u }{ r } .}

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