Question 2.41: A three-phase load has a resistance and reactance of 6 Ω eac...

V_{Ph}=\frac{V_{L}}{\sqrt{3}}=\frac{400}{\sqrt{3}}=231  V

Z_{Ph}=6 + j  6  Ω = 8.48 ⌊45°  Ω

I_{Ph}=\frac{V_{Ph}}{ Z_{Ph}}=\frac{231 ⌊0°}{ 8.48 ⌊45°}=27.2 ⌊-45°  A

I_{Ph}=I_{L}=27.2  A

Angle between V_{Ph} and I_{Ph} is 45°.
Power factor = \cos 45° = 0.7 lagging

Power absorbed by each phase of the load = V_{Ph}  I_{Ph}  \cos Φ

= 231 × 27.2 × 0.7
= 4398 W

(Total power consumed = 3 × 4398 = 13194 W