Holooly Plus Logo
Holooly Plus Logo

Question 6.9: a. Using data from Table 4.1 (see Appendix A, Data Tables), ...

a. Using data from Table 4.1 (see Appendix A, Data Tables), calculate K_{P} at 298.15 K for the reaction CO\left( g \right)+H_{2}O\left( l \right)\to CO_{2}\left( g \right)+H_{2}\left( g \right).

b. Based on the value that you obtained for part (a), do you expect the mixture to consist mainly of CO_{2}\left( g \right) and H_{2}\left( g \right) or mainly of CO\left( g \right)+H_{2}O\left( l \right) at equilibrium?

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

a.  \ln K_{P}=-\frac{1}{RT}\Delta G°_{R}

 

=-\frac{1}{R}\left( ^{\Delta G°_{f}\left( CO_{2,g} \right)+\Delta G°_{f}\left( H_{2,g} \right)-\Delta G°_{f}\left( H_{2} O,l\right)} _{-\Delta G°_{f}\left( CO,g \right)}\right)

 

=-\frac{1}{8.314 J mol^{-1} K^{-1} ×298.15 K}

 

×\left( ^{-394.4 ×10^{3}J mol^{-1}+0+237.1}_{×10^{3}J mol^{-1}+137.2 ×10^{3}J mol^{-1}} \right)

 

=8.1087

 

k_{P}=3.32 ×10^{3}

b.  Because K_{P}\gg 1, the mixture will consist mainly of the products CO_{2}\left( g \right)+H_{2}\left( g \right) at equilibrium.

Related Answered Questions

Question: 6.11

Using the result of Example Problem 6.10 and the data tables, consider the dissociation equilibrium Cl2(g)→←2Cl(g).a. Calculate KP at 800. K, 1500. K, and 2000. K for P=0.010 bar. b. Calculate the degree of dissociation α at 300. K, 1500. K, and 2000. K. ...

Verified Answer:

a.   \Delta G°_{R}=2\Delta G°_{f}\left( Cl,...
Question: 6.10

In this example, n0 moles of chlorine gas are placed in a reaction vessel whose temperature can be varied over a wide range, so that molecular chlorine can partially dissociate to atomic chlorine. a. Define the degree of dissociation as α=δeq/n0 , where is 2δeq the number of moles of Cl(g) ...

Verified Answer:

a. We set up the following table: Cl_{2...
Question: 6.16

In the previous Example Problem, it was assumed that CP=CV. a. Use equation 3.38, CP,m=Cv,m +TVm β²/κ, and the experimentally determined value CP,m=27.98 J mol-¹ to obtain a value for CV,m for Hg(l) at 300. K.b. Did the assumption that CP,m≈CV,m in Example Problem 6.15 introduce an appreciable ...

Verified Answer:

a.   C_{P,m}-C_{V,m}=\frac{TV_{m}\beta^{2}}...
Question: 6.15

A 1000. g sample of liquid Hg undergoes a reversible transformation from an initial state Pi = 1.00 bar , Ti=300. K to a final state Pf =300. bar, Tf=600. K. The density of Hg is 13,534 kg m-³,β =1.81× 10^-4 K-¹, CP=27.98 J mol-¹ K-¹, and κ =3.91 × 10^-6 bar-¹, in the range of the variables in this ...

Verified Answer:

Because U is a state function, \Delta U[/la...
Question: 6.17

Calculate the conventional molar Gibbs energy of (a) Ar(g) and (b) H2O(l) at 1 bar and 298.15 K. ...

Verified Answer:

a. Because Ar \left( g\right) is an...
Question: 6.14

At 298 K, the thermal expansion coefficient and the isothermal compressibility of liquid water are β =2.04 × 10-^4 K-¹ and κ =45.9 × 10-^6 bar-¹.a. Calculate (∂U/∂V)T  for water at 320. K and Ρ= 1.00 bar. b. If an external pressure equal to (∂U/∂V)T were applied to 1.00 m³ of liquid water at 320.K ...

Verified Answer:

a. \left( \frac{\partial U}{\partial V} \ri...
Question: 6.13

At 298.15 K ΔG°f (C,graphite) =0, and ΔG°f (C,diamond)  =2.90 KJ mol-¹ Therefore, graphite is the more stable solid phase at this temperature at P=P°=1 bar . Given that the densities of graphite and diamond are 2.25 and 3.52 kg L, respectively, at what pressure will graphite and diamond be in ...

Verified Answer:

At equilibrium \Delta G =G\left( C, graphit...
Question: 6.12

Using the preceding discussion and the tabulated values of ΔG°f and ΔH°f in Appendix A, calculate the CO2(g) pressure in equilibrium with a mixture of  CaCO3(s) and CaO(s) at 1000.,1100.,and 1200. K. ...

Verified Answer:

For the reaction CaCo_{3}\left( s \right) \...
Question: 6.8

NO2(g) and N2O4(g) are in a reaction vessel with partial pressures of 0.350 and 0.650 bar, respectively, at 298 K. Is this system at equilibrium? If not, will the system move toward reactants or products to reach equilibrium? ...

Verified Answer:

The reaction of interest is 2 NO_{2}\left( ...
Question: 6.7

Calculate  ΔG°R for the reaction in Example Problem 6.6 at 325 K. Is the reaction spontaneous at this temperature?  ...

Verified Answer:

To calculate \Delta G°_{R} at the e...