Question 5.1: An abrupt Si p-n junction has Na = 10^18 cm^-3 on one side a...

An abrupt Si p-n junction has N_{d} = 10^{18} cm^{-3} on one side and N_{d} =5× 10^{15} cm^{-3} on the other.
(a) Calculate the Fermi level positions at 300 K in the p and n regions.
(b) Draw an equilibrium band diagram for the junction and determine the contact potential V_{0} from the diagram.
(c) Compare the results of part (b) with V_{0} as calculated from Eq. (5–8).

V_{0}=\frac{kT}{q} \ln \frac{N_{a}} {n^{2}_{i}/N_{d} } =\frac{kT}{q} \ln \frac{N_{a} N_{d}}{n^{2}_{i}}  (5–8)