Question 2.35: An inductive coil has a resistance of 10 Ω and inductance of...

An inductive coil has a resistance of 10 Ω and inductance of 100 mH. This coil is connected in parallel with a capacitor of 20 μF. A variable frequency power at 100 V is applied across this parallel circuit. Calculate the frequency at which the circuit will reasonate. Also calculate the Q-factor, dynamic impedance of the circuit, and resonant current.

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Resonant frequency,             f_{0}=\frac{1}{2π}\sqrt{\frac{1}{LC}  –  \frac{R²}{L²}}  

Substituting the given values,

f_{0}=\frac{1}{2π}\sqrt{\frac{1}{100  ×  10^{-3}  ×  20  ×  10^{-6}}  –  \frac{(10)²}{(100  ×  10^{-3})²}}  

=112.48  Hz

Q-factor = \frac{2πf_{0}L}{R}=\frac{6.28  ×  112.48  ×  100 ×  10^{-3}}{10} = 7.06

Dynamic impedance,                  Z_{0}=\frac{L}{CR}=\frac{100  ×  10^{-3}}{20  ×  10^{-6}  ×  10}= 500  Ω

Current at resonance,                I_{0}=\frac{V}{Z_{0}}=\frac{100}{500} = 0.2  A

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