## Chapter 14

## Q. 14.8

As shown schematically in Figure 14.31, square columns 4 in. × 4 in. and 10 ft tall are to be used in the construction of a porch in south Florida. If the columns are exposed to hurricane force winds of 100 mph(= 147 ft/s), what force must each column withstand?

## Step-by-Step

## Verified Solution

The Reynolds number of the ﬂow is found to be

Re=\frac{UD}{\nu}=\frac{(147\ \mathrm{ft}/s)(4\ in.)(\mathrm{ft}/12 in.)}{1.64×10^{−4}\ \mathrm{ft}^2/s }=3\times 10^5

which is above the value Re > 10^{4} for which the data for a square section in Table 14.3 are valid. Thus it is appropriate to use the drag coefficient in this table for our analysis. In Table 14.3 we see that for a square section, the maximum C_{D} = 2.4 is at 45° angle to the wind, thus the maximum force will occur for a wind that comes from this direction. This is the force the column must potentially withstand in the worst case. To calculate it, we will assume 70°F air and use A = (4/12 ft)(10 ft) = 3.33 ft^{2} and U = 147 ft/s. The drag force is then found to be

F_{D} = \frac{1}{2} ρU^{2}AC_{D} = \frac{1}{2} (2.329 × 10^{−3} slug/ft^{3})[147 ft/s]^{2}(3.33 ft^{2})(2.4) = 200 lb_{f}

**TABLE 14.3 Drag Coefficients for selected 2D sections.**

Geometry | Drag Coefficient, C_{D}, and Remarks |
||||||||||||||||||||||

Re ≥ 10^4 |