Question 11.10: Calculate [H3O^+] for a urine sample, which has a pH of 7.5.
Calculate [H_{3}O^{+}] for a urine sample, which has a pH of 7.5.
STEP 1 State the given and needed quantities.
| ANALYZE THE PROBLEM | Given | Need | Connect |
| pH = 7.5 | [H_{3}O^{+}] | [H_{3}O^{+}] = 10^{-PH} |
STEP 2 Enter the pH value into the inverse log equation and calculate.
[H_{3}O^{+}] = 10^{-PH} = 10^{-7.5} \overset{Calculator Procedure}{\boxed{2^{nd}} \boxed{\log} \boxed{+/-} 7.5 \boxed{=}} or 7.5 \boxed{+/-} \boxed{2^{nd}} \boxed{\log} \boxed{=} \overset{Calculator Display}{\boxed{3.16227766E-08}}STEP 3 Adjust the SFs for the coefficient. Because the pH value 7.5 has one digit to the right of the decimal point, the coefficient for [H_{3}O^{+}] is written with one SF.
\underset{One SFs}{[H_{3}O^{+}] =3 \times 10^{-8} M}Related Answered Questions
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ANALYZE THE PROBLEM
Given
Need
Connect
HB...