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Question 10.4: Calculate the amount of heat (in kJ) required to heat 255 g ...

Calculate the amount of heat (in \text{kJ}) required to heat 255  \text{g} of water from 25.2°\text{C} to 90.5°\text{C}.

Strategy Use Equation 10.11 (q = sm∆T) to calculate q.

Setup s = 4.184  \text{J/g ⋅ °C}, m = 255  \text{g}, and ∆T = 90.5°\text{C} – 25.2°\text{C} = 65.3°\text{C}.

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q = \frac{4.184  \text{J}}{\text{g ⋅ °C}} × 255  \text{g} × 65.3°\text{C} = 6.97 × 10^4 \text{J} or 69.7  \text{kJ}

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