Calculate the mass of water (in g) that can be vaporized at its boiling point with 155 kJ of heat.

Question

SORT You are given a certain amount of heat in kilojoules and asked to find the mass of water that can be vaporized.

GIVEN 155 kJ
FIND: g H[latex]_{2}[/latex]O

STRATEGIZE The heat of vaporization gives the relationship between heat absorbed and moles of water vaporized. Begin with the given amount of heat (in kJ) and convert to moles of water that can be vapor-ized. Then use the molar mass as a conversion factor to convert from moles of water to mass of water.

CONCEPTUAL PLAN

kJ → mol H[latex]_{2}[/latex]O → g H[latex]_{2}[/latex]O

. [latex]\frac{1molH_{2}O}{40.7kJ}[/latex] [latex]\frac{18.02gH_{2}O}{1molH_{2}O}[/latex]

RELATIONSHIPS USED
∆H[latex]_{vap}[/latex] = 40.7 kJ/mol (at 100 °C)
18.02 g H[latex]_{2}[/latex]O = 1 mol H[latex]_{2}[/latex]O

SOLVE Follow the conceptual plan to solve the problem.

Accepted Answer

155[latex]\cancel{kJ} imes\frac{1\cancel{molH_{2}O}}{40.7\cancel{kJ}} imes\frac{18.02gH_{2}O}{1\cancel{molH_{2}O}}=68.6gH_{2}O[/latex]

Question 11.3: Calculate the mass of water (in g) that can be vaporized at ...

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