Question 7.8: Calculate the molar mass for lithium carbonate, Li2CO3, used...
Calculate the molar mass for lithium carbonate, Li_{2}CO_{3}, used to treat bipolar disorder.
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ANALYZE THE PROBLEM | Given | Need | Connect |
formula of Li_{2}CO_{3} | molar mass of Li_{2}CO_{3} | periodic table |
STEP 1 Obtain the molar mass of each element.
\begin{array}{r c}\boxed{\frac{6.941 g Li}{1 mole Li } } & \boxed{\frac{12.01 g C}{1 mole C } } & \boxed{\frac{16.00 g O }{1 mole O } } \end{array}STEP 2 Multiply each molar mass by the number of moles (subscript) in the formula.
Grams from 2 moles of Li:
Grams from 1 mole of C:
1 \cancel{mole C} \times \boxed{\frac{12.01 g C}{1 \cancel{ mole C} } }=12.01 g of CGrams from 3 moles of O:
3 \cancel{mole O} \times \boxed{\frac{16.00 g O}{1 \cancel{ mole O} } }=48.00 g of OSTEP 3 Calculate the molar mass by adding the masses of the elements.
2 moles of Li = 13.88 g of Li
1 mole of C = 12.01 g of C
3 moles of O = \underline{48.00 g of O}
Molar mass of Li_{2}CO_{3} = 73.89 g
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