Question 7.8: Calculate the molar mass for lithium carbonate, Li2CO3, used...

Calculate the molar mass for lithium carbonate, Li_{2}CO_{3}, used to treat bipolar disorder.

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ANALYZE THE PROBLEM Given Need Connect
formula of Li_{2}CO_{3} molar mass of Li_{2}CO_{3} periodic table

STEP 1   Obtain the molar mass of each element.

\begin{array}{r c}\boxed{\frac{6.941  g  Li}{1  mole  Li } } & \boxed{\frac{12.01  g  C}{1  mole  C } } & \boxed{\frac{16.00  g  O }{1  mole  O } } \end{array}

STEP 2   Multiply each molar mass by the number of moles (subscript) in the formula.
Grams from 2 moles of Li:

2  \cancel{moles  Li} \times \boxed{\frac{6.941  g  Li}{1  \cancel{ mole   Li} } }=13.88  g  of  Li

Grams from 1 mole of C:

1  \cancel{mole  C} \times \boxed{\frac{12.01  g  C}{1  \cancel{ mole  C} } }=12.01  g  of  C

Grams from 3 moles of O:

3  \cancel{mole  O} \times \boxed{\frac{16.00  g  O}{1  \cancel{ mole  O} } }=48.00  g  of  O

STEP 3   Calculate the molar mass by adding the masses of the elements.

2 moles of Li                                          = 13.88 g of Li
1 mole of C                                              = 12.01 g of C
3 moles of O                                            = \underline{48.00  g  of  O}
Molar mass of Li_{2}CO_{3}                          = 73.89 g

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