Question 4.5: Calculate the standard heat of reaction at 25°C for the foll...

Introduction to Chemical Engineering Thermodynamics

Calculate the standard heat of reaction at 25°C for the following reaction:

$4HCl(g) + O_{2} (g) → 2 H_{2} O(g) + 2 Cl_{2} (g)$

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Standard heats of formation at 298.15 K from Table C.4 are:

$HCl(g) : − 92,307 J H_{2} O(g) : −241,818 J$

The following combination gives the desired result:

4HCl ( g )  →  2  H_{2}( g )  + 2 Cl_{2} ( g )                ΔH^{°}_{298}  = ( 4 ) (92,307)

2 H _{2} ( g )  + O_{2} ( g ) → 2 H_{2} O ( g )                         ΔH^{°}_{298}   = ( 2 ) (−241,818)

4 HCl( g )  + O_{2} ( g )  →  2 H_{2} O( g )  + 2 Cl_{2} ( g )               ΔH^{°}_{298}  = −114,408 J

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