Question 16.11: CALCULATING FROM Ksp At 25 °C, for PbCrO4 is 2.8 × 10^-13. C...

CALCULATING FROM $K_{sp}$

At 25 °C, for $PbCrO_{4} is 2.8 × 10^{-13}$ . Calculate the standard free-energy change at 25 °C for the reaction $PnCrO_{4}(s) \rightleftharpoons Pb^{2+}(aq) + CrO_{4}^{2-}(aq)$

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