Question 4.1: CALCULATING THE CONCENTRATION OF IONS IN A SOLUTION What is ...
CALCULATING THE CONCENTRATION OF IONS IN A SOLUTION
What is the total molar concentration of ions in a 0.350 M solution of the strong electrolyte Na_{2}SO_{4}, assuming complete dissociation?
STRATEGY
First, we need to know how many ions are produced by dissociation of Na_{2}SO_{4}.
Writing the equation for dissolving Na_{2}SO_{4} in water shows that 3 mol of ions are formed: 2 mol of Na^{+} and 1 mol of SO_{4}^{2-}.
Na_{2}SO_{4}(s) \underrightarrow{H_{2}O} 2 Na^{+}(aq) + SO_{4}^{2-}(aq)
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Assuming complete dissociation, the total molar concentration of ions is three times the molarity of Na_{2}SO_{4}, or 1.05 M:
\frac{0.350 \cancel{mol Na_{2}SO_{4}}}{1 L} × \frac{3 mol ions}{1 \cancel{mol Na_{2}SO_{4}}} = 1.05 M
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