Question 4.1: CALCULATING THE CONCENTRATION OF IONS IN A SOLUTION What is ...

CALCULATING THE CONCENTRATION OF IONS IN A SOLUTION

What is the total molar concentration of ions in a 0.350 M solution of the strong electrolyte Na_{2}SO_{4}, assuming complete dissociation?

STRATEGY
First, we need to know how many ions are produced by dissociation of Na_{2}SO_{4}.
Writing the equation for dissolving Na_{2}SO_{4} in water shows that 3 mol of ions are formed: 2 mol of Na^{+} and 1 mol of SO_{4}^{2-}.

Na_{2}SO_{4}(s)  \underrightarrow{H_{2}O}  2  Na^{+}(aq)  +  SO_{4}^{2-}(aq)

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Assuming complete dissociation, the total molar concentration of ions is three times the molarity of Na_{2}SO_{4}, or 1.05 M:

\frac{0.350  \cancel{mol  Na_{2}SO_{4}}}{1  L}  ×  \frac{3  mol  ions}{1  \cancel{mol  Na_{2}SO_{4}}} = 1.05 M

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