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Question 3.11: CALCULATING THE MOLARITY OF A SOLUTION What is the molarity ...

CALCULATING THE MOLARITY OF A SOLUTION

What is the molarity of a solution made by dissolving 2.355 g of sulfuric acid (H_{2}SO_{4}) in water and diluting to a final volume of 50.0 mL?

STRATEGY
Molarity is the number of moles of solute per liter of solution. Thus, it’s necessary to find the number of moles of sulfuric acid in 2.355 g and then divide by the volume of the solution.

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Molec. mass of H_{2}SO_{4} = (2 × 1.0 amu) + 32.1 amu + (4 × 16.0 amu) = 98.1 amu

Molar mass of H_{2}SO_{4} = 98.1 g/mol

2.355  \cancel{g  H_{2}SO_{4}}  ×  \frac{1  mol  H_{2}SO_{4}}{98.1  \cancel{g  H_{2}SO_{4}}}  =  0.0240  mol  H_{2}SO_{4}

\frac{0.0240  mol  H_{2}SO_{4}}{0.0500  L} = 0.480 M

The solution has a sulfuric acid concentration of 0.480 M.

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