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Question 3.12: CALCULATING THE NUMBER OF MOLES OF SOLUTE IN A SOLUTION Hydr...

CALCULATING THE NUMBER OF MOLES OF SOLUTE IN A SOLUTION

Hydrochloric acid is sold commercially as a 12.0 M aqueous solution. How many moles of HCl are in 300.0 mL of 12.0 M solution?

STRATEGY

The number of moles of solute is calculated by multiplying the molarity of the solution by its volume.

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Moles of HCl = (Molarity of solution) × (Volume of solution)

= \frac{12.0  mol  HCl}{1  \cancel{L}}  ×  0.3000  \cancel{L} = 3.60 mol HCl

There are 3.60 mol of HCl in 300.0 mL of 12.0 M solution.

BALLPARK CHECK
One liter of 12.0 M HCl solution contains 12 mol of HCl, so 300 mL (0.3 L) of solution contains 0.3 × 12 = 3.6 mol.

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