Classify the monosaccharide shown as an aldose or a ketose, and name it according to its number of carbon atoms.

Question

[latex]\begin{array}{r c} \underset{|}{H} \enspace \; \underset{|}{H} \underset{|}{\quad OH } \underset{|}{H} \underset{|}{\quad OH } \underset{||}{O} \qquad \ HO - C - C - C - C - C - C - H \ \overset{|}{H} \overset{|}{ \quad OH } \overset{|}{H} \overset{|}{ \quad OH } \overset{|}{H} \qquad \quad \; \; \end{array}[/latex]

ANALYSIS First determine if the monosaccharide is an aldose or a ketose. Then determine the number of carbon atoms present. This monosaccharide is an aldose because an aldehyde group is present. It contains 6 carbon atoms.

Accepted Answer

The monosaccharide is a 6-carbon aldose, so we refer to it as an aldohexose.

Question 22.1: Classify the monosaccharide shown as an aldose or a ketose, ...

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