Question 8.9: Compute the maximum shearing stress that would occur in a ci...

Equation (8–15) will give the maximum shearing stress at the horizontal diameter of the

shaft:

\tau_{max} = \frac{4V}{3A}

But

A = \frac{\pi D^{2}}{4} = \frac{\pi(50  mm)^{2}}{4} = 1963 mm²

Then

\tau_{max} =  \frac{4(110 \times 10^{3}  N)}{3(1963  mm^{2})} = 74.7 MPa