Question 1.8: Compute the octal equivalent of the decimal number (231)10.
Compute the octal equivalent of the decimal number (231)_{10} .
(231)_{10}=2 \times 10^2+3 \times 10^1+1 \times 10^0=(2)_8 \times(12)_8^2+(3)_8 \times(12)_8+(1)_8
On using octal arithmetic in the Algorithm 1.1, we have
\begin{aligned} &b_2=a_2=(2)_8 \\ &b_1=a_1+b_2 \beta=(3)_8+(2)_8 \times(12)_8=(27)_8 \\ &b_0=a_0+b_1 \beta=(1)_8+(27)_8 \times(12)_8=(1)_8+(346)_8=(347)_8 \end{aligned}
Related Answered Questions
Question: 1.14
Verified Answer:
Let c_0=(. B 4)_{16}
[l...
Question: 1.13
Verified Answer:
Let c_0=(.71)_8
\be...
Question: 1.12
Verified Answer:
Using the algorithm 1.2 and binary arithmetic, we ...
Question: 1.10
Verified Answer:
Let c_0=(.3125)_{10}
[latex...
Question: 1.9
Verified Answer:
\begin{aligned} (2655)_{16} &=2 \times...
Question: 1.7
Verified Answer:
(231)_{10}=2 \times 10^2+3 \times 10^1+1 \...
Question: 1.6
Verified Answer:
(110111)_2=1 \times 2^5+1 \times 2^4+0 \ti...
Question: 1.5
Verified Answer:
\begin{array}{lll} 2655=165 \times 16+15 &...
Question: 1.4
Verified Answer:
\begin{array}{lll} 231=115 \times 2+1 &...
Question: 1.1
Verified Answer:
Decimal Arithmetic (For base 10, digits are 0 … 9)...