Consider a 25 X 5 two-dimensional array of students which has a base address 500 and where the size of each element is 2. Now calculate the address of the element student[15][3] assuming that the elements are stored in a) Row major order b) Column major order

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Accepted Answer

a) Row major order Here we are given that w = 2, base address = 500, n = 5, i = 15, j = 3.

Address( A[i][j] ) = Base address(BA) + w ( n( i-1 ) + ( j-1 ) )

Address( student[15][3] ) = 500 + 2 ( 5( 15-1 ) + ( 3-1 ) )

= 500 + 2 ( 5( 14 ) + 2 )

= 500 +2 ( 72 )

= 500 + 144

Address( student[15][3] ) = 644 b)

Column major order Here we are given that w = 2, base address = 500, m = 25, i = 15, j = 3

Address( A[i][j] ) = Base address(BA) + w ( m( j-1 ) + ( i-1 ) ) Address( student[15][3] ) = 500 + 2 ( 25( 3-1 ) + ( 15-1 ) )

= 500 + 2 ( 25( 2 ) + 14 )

= 500 +2 ( 64 )

Address( student[15][3] )

= 500 + 128

= 628

Question 3.FAQ.3: Consider a 25 X 5 two-dimensional array of students which ha...

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