Question 15.12: Consider Figure 15.26(a). Reflect Vs and R1 to the secondary...

The voltage is reflected by using the turns ratio. Thus, we have
\textbf{V}^′_s = \frac{N_2} {N_1} \textbf{V}_s = \frac{1} {10} 1000∠0° = 100∠0°

On the other hand, the resistance is reflected using the square of the turns ratio. This yields
R^′_1 = \left(\frac{N_2}{ N_1}\right) ^2 R_1 = \left(\frac{1}{ 10}\right) ^2 (1000) = 10 Ω
The circuit with \textbf{V}_s and R_1 transferred to the secondary side is shown in Figure 15.26(c).