Question 31.Q-Q.2: Consider the following decay: n → π^+ + π^- + µ^+ + µ^-. Wha...
Consider the following decay: n \rightarrow \pi^{+}+\pi^{-}+\mu^{+}+\mu^{-} . What conservation laws are violated by this decay? (a) energy (b) electric charge (c) baryon number (d) angular momentum (e) no conservation laws
(c), (d). There is a baryon, the neutron, on the left of the reaction, but no baryon on the right. Therefore, baryon number is not conserved. The neutron has spin \frac{1}{2} .
On the right side of the reaction, the pions each have integral spin, and the combination of two muons must also have integral spin. Therefore, the total spin of the particles on the right-hand side is integral and angular momentum is not conserved.
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