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Question 5.SP.18: Consider the reaction of ethylene (C2H4) and water to form e...

Consider the reaction of ethylene (C_{2}H_{4}) and water to form ethanol (C_{2}H_{6}O), which was mentioned in Section 5.8B. If the theoretical yield of ethanol is 23 g in a reaction, what is the percent yield of  ethanol if only 15 g of ethanol are actually formed?

Use the formula, percent yield = (actual yield/theoretical yield) × 100% to calculate the percent yield.

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\begin{matrix}\text{Percent yield }&= & \frac{\text{ctual yield (g)}}{\text{theoretical yield (g) }} & \times & 100\% \\ \\ & = & \frac{\text{15 g}}{\text{23 g}}& \times &100\% & = & 65\% \\  \\ &&&&&&\text{Answer} \end{matrix}

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