Question 4.5: Convert (a) 450 knots into kph and (b) 120 m/s into mph.

Convert (a) 450 knots into kph and (b) 120 m/s into mph.

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We could simply multiply by the relevant conversion factors in Table 4.7, which for (a) is the reciprocal of 0.5400 or 1.852. Similarly, for (b), the conversion factor is 2.23694. But let us see if we can derive these conversion factors by addressing the problem in a rather circular manner.

Quantity SI unit Conversion factor→ Imperial/other
recognized units
Acceleration metre/second² (m/s²) 3.28084 feet/second² (ft/s²)
Angular measure radian (rad) 57.296 degrees (°)
radian/second (rad/s) 9.5493 revolutions per minute
(rpm)
Area metre² (m²) 10.7639 feet² (ft²)
metre² (m²) 6.4516 × 10^4 inch² (in²)
Density kilogram/metre³ (kg/m³) 0.062428 pound/foot³ (lb/ft³)
kilogram/metre³ (kg/m³) 3.6127 × 10^{-5} pound/inch³ (lb/in³)
kilogram/metre³ (kg/m³) 0.010022 pound/gallon (UK)
Energy, work, heat joule (J) 0.7376 foot pound-force (ft lbf)
joule (J) 9.4783 × 10^{-4} British thermal unit (btu)
joule (J) 0.2388 calorie (cal)
Flow rate m³ /s (Q) 35.315 ft³ /s
m³ /s (Q) 13,200 gal/min (UK)
Force Newton (N) 0.2248 pound-force (lbf)
Newton (N) 7.233 poundal
kilo-Newton 0.1004 ton-force (UK)
Heat transfer watt (W) 3.412 btu/h
watt (W) 0.8598 kcal/h
watt/metre² kelvin (W/m² K) 0.1761 btu/h ft² °F
Illumination lux (lx) 0.0929 foot candle
lux (lx) 0.0929 lumen/foot² (lm/ft²)
candela/metre² (cd/m²) 0.0929 candela/ft² (cd/ft²)
Length metre (m) 1 × 1010 angstrom
metre (m) 39.37008 inch (in)
metre (m) 3.28084 feet (ft)
metre (m) 1.09361 yard (yd)
kilometre (km) 0.621371 mile
kilometre (km) 0.54 nautical miles
Mass kilogram (kg) 2.20462 pound (lb)
kilogram (kg) 35.27392 ounce (oz)
kilogram (kg) 35.27392 slug
tonne (t) 0.984207 ton (UK)
tonne (t) 1.10231 ton (US)
Moment, torque Newton-metre (Nm) 0.73756 foot pound-force (ft lbf)
Newton-metre (Nm) 8.8507 inch pound-force (in. lbf)
Moment of inertia (mass) kilogram-metre squared (kgm²) 0.7376 slug-foot squared (slug ft²)
Second moment of area millimeters to the fourth (mm^4) 2.4 × 10^{-6} inch to the fourth (in^4)
Power watt (W) 3.4121 British thermal unit/hour
(btu/h)
watt (W) 0.73756 foot pound-force/second
(ft lbf/s)
kilowatt (kW) 1.341 horsepower
horsepower (hp) 550 foot pound-force/second
(ft.lbf/s)
Pressure, stress kilopascal (kPa) 0.009869 atmosphere (atm)
kilopascal (kPa) 0.145 pound-force/inch² (psi)
kilopascal (kPa) 0.01 bar
kilopascal (kPa) 0.2953 inches of mercury
pascal 1.0 Newton/metre² (N/m²)
megapascal (MPa) 145.0 pound-force/inch² (psi)
Temperature kelvin (K) 1.0 celsius (C)
kelvin (K) 1.8 rankine (R)
kelvin (K) 1.8 fahrenheit (F)
kelvin (K) °C + 273.15
kelvin (K) (°F + 459.67)/1.8
celsius (°C) (°F – 32)/1.8
Velocity metre/second (m/s) 3.28084 feet/second (ft/s)
metre/second (m/s) 196.85 feet/minute (ft/min)
metre/second (m/s) 2.23694 miles/hour (mph)
kilometre/hour (kph) 0.621371 miles/hour (mph)
kilometre/hour (kph) 0.5400 knot (international)
Viscosity (kinematic) square    metre/second
(m² /s)
1 × 10^{6} centi-stoke
square    metre/second
(m² /s)
1 × 10^{4} stoke
square    metre/second
(m² /s)
10.764 square feet/second
(ft² /s)
Viscosity (dynamic) pascal second (Pa s) 1000 centipoise (cP)
centipoise (cP) 2.419 pound/feet hour (lb/ft h)
Volume cubic metre (m³) 35.315 cubic feet (ft³)
cubic metre (m³) 1.308 cubic yard (yd³)
cubic metre (m³) 1000 litre (l)
litre (l) 1.76 pint (pt) UK
litre (l) 0.22 gallon (gal) UK

a)      Suppose we know that there are 6080 ft in a knot. Then, since there are 3.28084 ft in 1 m, there are \frac{6080}{3.28084} = 1853.18 m in a knot.

Therefore, 450 knots = 450 × 1853.18 m/h or 833.93 kph.

Thus, to convert knots to kph, we need to multiply them by \frac{833.93}{450} = 1.853, which to two decimal places agrees with our tabulated value.

b)      A conversion factor to convert m/s into mph may be found in a similar manner. In this case we start with the fact that 1 m = 3.28084 ft and there are 5280 ft in a mile, so:

120 m/s = 3.28.04 × 120 feet per second

or

\frac{3.28084 \times 120}{5280} miles per second

We also know that there are 3600 s in an hour. Therefore:

\begin{aligned}120 \ m / s &=\frac{3.28084} \times 120 \times {3600}{5280} \\&=268.4 \ mph\end{aligned}

Again the multiplying factor is given by the ratio 268.4/120 = 2.2369, which is in agreement with our tabulated value.

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