Question 12.6: Convert the following line structures to condensed structure...
Convert the following line structures to condensed structures:
(a) 
(b) 
ANALYSIS Convert all vertices and line ends to carbons. Write in any noncarbon atoms and any hydrogens bonded to a noncarbon atom. Add hydrogens as needed so that each carbon has four groups attached. Remove lines connecting carbons except for branches.
(a) Anywhere a line ends and anywhere two lines meet, write a C:
Because there are no atoms other than carbons and hydrogens in this molecule, the next step is to add hydrogens as needed to have four bonds for each carbon:
Finally, eliminate all lines except for branches to get the condensed structure:
\begin{array}{r c} \underset{|}{\quad \; CH_3} \qquad \quad \\ CH_3CH_2 \; C \; CH_2CH_3 \\ \overset{|}{ \qquad \quad \; CH_2CH_3} \quad \end{array}(b) Begin the condensed structure with a drawing showing a carbon at each line end and at each intersection of two lines:
Next write in all the noncarbon atoms and the hydrogen bonded to the oxygen. Then add hydrogens so that each carbon forms four bonds:
Eliminate all lines except for branches for the completed condensed structure:
\begin{array}{r c} \underset{|}{\quad \; CH_3} \qquad \enspace \\ HOCH_2 \; C \; CH_2Br \\ \overset{|}{ \enspace \; \; NH_2} \qquad \enspace \end{array}