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Question 2.21: Dependent Source Find the current, Ix, that is shown in Figu...

Dependent Source

Find the current, I_x, that is shown in Figure 2.57.

2.21
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Here, the current direction is arbitrarily selected to be counterclockwise, which is the opposite direction of the voltage source, 5 V. Using the values from Figure 2.57, the equation is:

5I_x = 50I_x + 5

Therefore, the current, I_x, is:

\begin{aligned}-45I_x &= 5\\I_x &= -0.11  A\end{aligned}

The negative sign of the current shows that the correct current direction is clockwise instead of counterclockwise, as shown in Figure 2.57.

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