Question 15.14: Depreciation and Inflation Copper River Valves is evaluating...
Depreciation and Inflation
Copper River Valves is evaluating some manufacturing equipment whose first cost is $250K. The operating costs are $45K per year in year-0 dollars, and the salvage value is $0 after 10 years. The firm’s real after-tax interest rate is 9%, and the firm’s profits average $40 million per year. Inflation is expected to average 7% over the next 10 years. What is the EAC of this equipment? How much higher or lower is this than the value that ignores inflation?
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Since the operating costs are stated in year-0 dollars, the first cost will be as well. Then, which values are affected by f, the inflation rate? The first cost is at time 0, so it is not affected. However, the depreciation deduction is affected, and it has a differential inflation rate found using Equation 15.3 of f_{Δdepr.} = −6.54%. The annual $45K in operating cost is best assumed to have no differential inflation. Thus, the easiest way to include inflation is to convert the depreciation deduction from nominal to year-0 dollars.
1+f_{\Delta item} = \frac{1+ f_{item}}{1+f} (15.3)
From Exhibit 12.7, manufacturing equipment has a 7-year recovery period for MACRS. The VDB function (see Section 12.9) is used to compute the MACRS deduction in column B of Exhibit 15.11. Column C uses the differential inflation rate to state this tax deduction in year-0
EXHIBIT 12.7 Recovery periods for MACRS
Description of Assets Included | Recovery Period |
Tractors for over-the-road tractor/trailer use and special tools such as dies and jigs; ADR < 4 years | 3-Year |
Cars, buses, trucks, computers, office machinery, construction equipment, and R&D equipment; 4 years ≤ADR < 10 years | 5-Year |
Office furniture, most manufacturing equipment, mining equipment, and items not otherwise classified; 10 years ≤ADR < 16 years | 7-Year |
Marine vessels, petroleum refining equipment, single-purpose agricultural structures, trees and vines that bear nuts or fruits; 16 years ≤ ADR < 20 years | 10-Year |
Roads, shrubbery, wharves, steam and electric generation and distribution systems, and municipal wastewater treatment facilities; 20 years ≤ ADR < 25 years | 15-Year |
Farm buildings and municipal sewers; ADR ≥ 25 years | 20-Year |
Residential rental property | 27.5-Year |
Nonresidential real property purchased on or before 5/12/93 | 31.5-Year |
Nonresidential real property purchased on or after 5/13/93 | 39-Year |
EXHIBIT 15.11 Depreciation and inflation at Copper River Valves
F | E | D | C | B | A | |
first cost for capital equipment | $250,000 | 1 | ||||
MACRS class | 7 | 2 | ||||
N | 10 | 3 | ||||
operations cost | $45,000 | 4 | ||||
f = CPI | 7% | 5 | ||||
f(delta-depreciation) | -6.54% | 6 | ||||
tax rate | 35% | 7 | ||||
real interest rate | 9% | 8 | ||||
9 | ||||||
ATCF(t) in year-0 $s |
Tax | Taxable Income w/ Operations Cost |
MACRS Deduction Constant $ |
MACRS Deduction Nominal $ |
Year | 10 |
-250,000 | 0 | 11 | ||||
-17,568 | -27,432 | -78,378 | 33,378 | 35,714 | 1 | 12 |
-10,533 | -34,467 | -98,476 | 53,476 | 61,224 | 2 | 13 |
-16,756 | -28,244 | -80,698 | 35,698 | 43,732 | 3 | 14 |
-20,909 | -24,091 | -68,831 | 23,831 | 31,237 | 4 | 15 |
-23,682 | -21,318 | -60,908 | 15,908 | 22,312 | 5 | 16 |
-24,046 | -20,954 | -59,868 | 14,868 | 22,312 | 6 | 17 |
-24,387 | -20,613 | -58,895 | 13,895 | 22,312 | 7 | 18 |
-26,977 | -18,023 | -51,493 | 6,493 | 11,156 | 8 | 19 |
-29,250 | -15,750 | -45,000 | 9 | 20 | ||
-29,250 | -15,750 | -45,000 | 10 | 21 | ||
PW= -$385,166 | 22 | |||||
PMT= -$60,017 | 23 |
dollars. (Since the first cost is at time 0 and the tax deduction is at the end of the first year, Equation 15.1 is used.)
F_{T+t} = F_{T} (1 + f )^{t} (15.1)
Column D shows the taxable income in year-0 dollars. This is computed by subtracting the column C values from the operations cost of −$45,000 ($A$4). Column E computes the tax savings, or negative tax, from the costs of this equipment by multiplying each year’s value in column D times the tax rate shown in cell $A$6. From Chapter 13, that tax rate is 35% with $40M in pretax profits.
Column F computes the ATCF by subtracting the negative tax in column E from the operations cost of −$45,000 in $A$4. The function NPV(A7,F11:F20) + F10 is used to find in year-0 dollars the PW of −$385,166. The EAC is found by multiplying this value by (A/P,9%,10), or .1558, to get $60,017.
To calculate the value ignoring inflation’s impact on depreciation, the easiest approach is to change the differential inflation rate for the MACRS deduction to 0%, as shown in Exhibit 15.12. At −$372,685, the PW is better (less negative) when ignoring inflation, since the MACRS deduction is larger in year-0 dollars. The EAC is $58,072, which is $1945 or 3.2% lower. While this difference is small, in some industries profits are less than 10% of costs, so this difference could amount to half of the potential profits linked to this machinery.
EXHIBIT 15.12 Ignoring inflation’s impact on depreciation at Copper River Valves
F | E | D | C | B | A | |
first cost for capital equipment | $250,000 | 1 | ||||
MACRS class | 7 | 2 | ||||
N | 10 | 3 | ||||
operations cost | $45,000 | 4 | ||||
f = CPI | 0% | 5 | ||||
f(delta-depreciation) | 0.00% | 6 | ||||
tax rate | 35% | 7 | ||||
real interest rate | 9% | 8 | ||||
9 | ||||||
ATCF(t) in year-0 $s |
Tax | Taxable Income w/ Operations Cost |
MACRS Deduction Constant $ |
MACRS Deduction Nominal $ |
Year | 10 |
-250,000 | 0 | 11 | ||||
-16,750 | -28,250 | -80,714 | 35,714 | 35,714 | 1 | 12 |
-7,821 | -37,179 | -106,224 | 61,224 | 61,224 | 2 | 13 |
-13,944 | -31,056 | -88,732 | 43,732 | 43,732 | 3 | 14 |
-18,317 | -26,683 | -76,237 | 31,237 | 31,237 | 4 | 15 |
-21,441 | -23,559 | -67,312 | 22,312 | 22,312 | 5 | 16 |
-21,441 | -23,559 | -67,312 | 22,312 | 22,312 | 6 | 17 |
-21,441 | -23,559 | -67,312 | 22,312 | 22,312 | 7 | 18 |
-25,345 | -19,655 | -56,156 | 11,156 | 11,156 | 8 | 19 |
-29,250 | -15,750 | -45,000 | 9 | 20 | ||
-29,250 | -15,750 | -45,000 | 10 | 21 | ||
PW= -$372,685 | 22 | |||||
PMT= -$58,072 | 23 |