Question 22.7: Derive the amino acid sequence that is coded for by the foll...

General, organic, & biological chemistry

Derive the amino acid sequence that is coded for by the following mRNA sequence.

5′ CAU AAA ACG GUG UUA AUA 3′

Analysis

Use Table 22.3 to identify the codons that correspond to each amino acid. Codons are written from the 5 ‘ to 3 ‘ end of an mRNA molecule and correspond to a peptide written from the N-terminal to C-terminal end.

Table 22.3 The Genetic Code—Triplets in Messenger RNA
First Base (5′ end)	Second Base								Third Base (3′ end)
	U		C		A		G
U	UUU	Phe	UCU	Ser	UAU	Tyr	UGU	Cys	U
	UUC	Phe	UCC	Ser	UAC	Tyr	UGC	Cys	C
	UUA	Leu	UCA	Ser	UAA	Stop	UGA	Stop	A
	UUG	Leu	UCG	Ser	UAG	Stop	UGG	Trp	G
C	CUU	Leu	CCU	Pro	CAU	His	CGU	Arg	U
	CUC	Leu	CCC	Pro	CAC	His	CGC	Arg	C
	CUA	Leu	CCA	Pro	CAA	Gln	CGA	Arg	A
	CUG	Leu	CCG	Pro	CAG	Gln	CGG	Arg	G
A	AUU	Ile	ACU	Thr	AAU	Asn	AGU	Ser	U
	AUC	Ile	ACC	Thr	AAC	Asn	AGC	Ser	C
	AUA	Ile	ACA	Thr	AAA	Lys	AGA	Arg	A
	AUG	Met	ACG	Thr	AAG	Lys	AGG	Arg	G
G	GUU	Val	GCU	Ala	GAU	Asp	GGU	Gly	U
	GUC	Val	GCC	Ala	GAC	Asp	GGC	Gly	C
	GUA	Val	GCA	Ala	GAA	Glu	GGA	Gly	A
	GUG	Val	GCG	Ala	GAG	Glu	GGG	Gly	G

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