Question 7.2: Determine the energy flux densities of the incident, reflect...

Determine the energy flux densities of the incident, reflected and transmitted waves. Verify the conservation of energy at the interface.

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The vector energy flux density of an acoustic wave has the components  S_i=-B\sum\limits_{j}\dot{u} _j(\partial u_j/\partial x_i) . Taking the real parts of the waves [7.28] and using the expressions of the reflection and transmission coefficients, we obtain:

\underline{u} =e\underline{u} _me^{i(ωt-ke.r)} \ , \ \ \ \ \underline{u^\prime} =e^\prime \underline{u} _m^\prime e^{i(ωt-k^\prime e^\prime .r)} \ , \ \ \ \ \ \underline{u}^{\prime \prime} =e^{\prime \prime} \underline{u} _m^{\prime \prime} e^{i(ωt-k^{\prime \prime}e^{\prime \prime}.r)}                     [7.28]

S_i=e_ikB_1ωu_m^2 \sin^2(ωt-ke.r) \ \ \ \Rightarrow \ \ \ S=eZ_1ω^2u_m^2 \sin^2(ωt-ke.r) \\ S^\prime _i=e^\prime _ikB_1ω{u^\prime _m}^2 \sin^2(ωt-k^\prime e^\prime .r) \ \ \ \Rightarrow \ \ \ S^\prime =e^\prime Z_1ω^2R_u^2 u_m^2 \sin^2(ωt-ke^\prime .r) \\ S^{\prime \prime}_i=e^{\prime \prime}_ik^{\prime \prime}B_1ω{u^{\prime \prime}_m}^2 \sin^2(ωt-k^{\prime \prime}e^{\prime \prime}.r) \ \ \ \Rightarrow \ \ \ S^{\prime \prime}=e^{\prime \prime}Z_2ω^2 7_u^2u_m^2 \sin^2(ωt-k^{\prime \prime}e^{\prime \prime}.r) .

To verify the conservation of energy, let us consider an element of area dS of the interface. The power that dS receives from medium (1) toward the positive z is

dS(S+S^\prime).e_z=dS\left[(e.e_z)+(e^\prime.e_z)R_u^2\right] Z_1ω^2u_m^2 \sin^2(ωt-ke.r) \\ =dS( \cos \theta -\cos \theta ^\prime R_u^2)Z_1ω^2u_m^2 \sin^2(ωt-ke.r).

The transmitted power across dS toward the positive z in medium (2) is

dS(S^{\prime \prime}.e_z)=dS(e^{\prime \prime}.e_z) 7_u^2Z_2ω^2u_m^2 \sin^2(ωt-k^{\prime \prime}e^{\prime \prime}.r) \\ =dS \cos\theta ^{\prime \prime} 7_u^2Z_2ω^2u_m^2 \sin^2(ωt-k^{\prime \prime}e^{\prime \prime}.r)

As ωt-k^{\prime \prime}e^{\prime \prime}.r=ωt-ke.r on the interface, the conservation of energy may be written in the form Z_1(1-R_u^2) \cos \theta =Z_2 7_u^2 \cos\theta ^{\prime \prime}, which is verified by the expressions of [7.30] for R_u and 7_u .

R_u\equiv \frac{\underline{u^\prime}_m }{\underline{u}_m } =\frac{Z_2 \cos\theta -Z_1 \cos\theta ^{\prime \prime}}{Z_2 \cos\theta +Z_1 \cos\theta ^{\prime \prime}} , \ \ \ \ \ \ 7_u\equiv \frac{\underline{u^{\prime \prime}}_m }{\underline{u}_m } =\frac{2Z_1 \cos\theta }{Z_2 \cos\theta +Z_1 \cos\theta ^{\prime \prime}}                       [7.30]

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