Question 5.3: Determine the five-digit Opitz code for the part shown in Fi...
Determine the five-digit Opitz code for the part shown in Fig. 5.25.
The attributes and dimensions of the part in Fig. 5.25 are used to assign the values of the digits in the Opitz code scheme as below.
(1) The overall length (L) and diameter (D) of the part are 1.50 and 2.50, respectively; therefore, L/D = 1.0 and the first digit becomes ‘1’.
(2) The part is rotational and has the steps at both ends but with one thread; therefore, the second digit is ‘5’.
(3) The part has an internal shape with a through-hole; therefore, the third digit is ‘1’.
(4) The part has no machined surface, therefore, the fourth digit is ‘0’.
(5) The part has no other holes or gear teeth, the fifth digit is ‘0’.
Therefore, the five-digit Opitz code of the part in Fig. 5.25 becomes ‘15100’.
Other than the first nine digits as the form code and the supplementary code, a complete Optiz code scheme uses additional four digits to represent other manufacturing attributes. Each digit has the options of 10 different values. Therefore, the Opitz code scheme has the capacity of representing a large number of product families for a wide scope of applications.