Question 17.3: Determine the membrane ligament efficiency in a header where...
Determine the membrane ligament efficiency in a header where t_{1} =t_{2} =1.50 in. The header contains a series of openings on 4 in. centers. The openings are multidiameter, as shown in Figure 17.8.

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Calculate the equivalent diameter D_{E} using Eq. (17.4) as follows:
D_{ E }=\frac{1}{t}\left(d_{0} T_{0}+d_{1} T_{1}+d_{2} T_{2}+\cdots+d_{n} T_{n}\right) (17.4)
p = 4in.
d_{0} = 1.625in. T_{0} = 0.125in.
d_{1} = 1.5in. T_{1} = 1.125in.
d_{2} = 1.375in. T_{2} = 0.25in.
D_{ E }=\frac{1.00}{1.50} × (1.625 × 0.125 + 1.5 × 1.125 + 1.375 × 0.25)
= 1.490in.
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