Question 10.1: Determine the molecular geometry of NO3^-.
Determine the molecular geometry of NO_{3}^{-}.
| Determine the molecular geometry of NO_{3}^{-} by counting the number of electron groups around the central atom (N). Begin by drawing a Lewis structure of NO_{3}^{-}. | NO_{3}^{-} has 5 + 3(6) + 1 = 24 valence electrons. The Lewis structure is:
The hybrid structure is intermediate between these three and has three equivalent bonds. |
| Use the Lewis structure, or any one of the resonance structures, to determine the num-ber of electron groups around the central atom. | 
The nitrogen atom has three electron groups. |
| Based on the number of electron groups, determine the geometry that minimizes the repulsions between the groups. | The electron geometry that minimizes the repulsions between three electron groups is trigonal planar. Because there are no lone pairs on the central atom, the molecular
geometry is also trigonal planar. |
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