Question 16.6: Determine the optimum overlap for a simple lap joint for 1/1...
Determine the optimum overlap for a simple lap joint for 1/16 in. sheet metal if the maximum load is 250 N/mm wide. Use the Araldite for which data are given in Figure 16.24.
Selecting a safety factor of 2 to accommodate uncertainty in the loading conditions, the design load becomes 500 N/mm. The tensile stress in the metal is given by
\sigma=\frac{P}{t}=\frac{500 \times 10^{3}}{(1 / 16) \times 25.4 \times 10^{-3}}=315.0 MPa\sigma=\frac{\tau}{t / L}=315 MPa
\tau=315 t / L
Plotting this line in Figure 16.24 gives the intercept shear stress of approximately 28 MPa and t/L = 0.09.
With t = 1.59 mm, L = 17.6 mm.
The optimum overlap is therefore 17.6 mm.
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